LET General Education Mathematics: Distance, Rate and Time
Distance, rate, and time problems are common applications of basic mathematics. Understanding the relationship among these three quantities can help you solve travel and speed problems in the LET General Education examination.
Practice Question
A car is able to travel 210 km in 3 hours. How far can it travel in 8 hours?
- 600 km
- 560 km
- 500 km
- 660 km
Correct Answer: B. 560 km
Solution and Explanation
This problem involves the relationship between distance, speed or rate, and time. We assume that the car maintains a constant speed throughout the journey.
The basic formula is:
Distance = Rate × Time
To solve the problem, we first need to determine the car's speed.
Step 1: Find the Speed
Given:
- Distance = 210 km
- Time = 3 hours
Use the formula:
Speed = Distance ÷ Time
Speed = 210 ÷ 3
Speed = 70 km/hour
This means that the car travels 70 kilometers every hour.
Step 2: Calculate the Distance in 8 Hours
Now that we know the speed, multiply it by the new travel time.
Distance = Rate × Time
Distance = 70 × 8
Distance = 560 km
Therefore, the car can travel 560 kilometers in 8 hours, assuming its speed remains constant.
Alternative Method: Using Proportion
Since the speed is constant, distance and time are directly proportional.
Set up the proportion:
210 / 3 = x / 8
Cross-multiply:
3x = 210 × 8
3x = 1,680
x = 1,680 ÷ 3
x = 560 km
Board Exam Tip
Remember these three formulas:
- Distance = Rate × Time
- Rate = Distance ÷ Time
- Time = Distance ÷ Rate
Quick Reminder: When speed is constant, distance increases as travel time increases. Always identify the given values and determine which quantity the question asks you to find.
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Disclaimer: This content is intended for educational review and practice purposes only. It is not an official PRC publication or examination material.